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I'm not 100% sure what the question is asking but I would suggest with $\displaystyle f(x) = \frac{2^{n}-5^{n+1}}{3^{n}+5^{n}}$ as $\displaystyle n \to \infty$ then $\displaystyle f(x) \to -1$
Originally Posted by fearsking Divide the numerator and denominator of the expression by 5^n: $\displaystyle \lim_{n \rightarrow + \infty} \frac{ \left( \frac{2}{5}\right)^n - 5}{\left( \frac{3}{5}\right)^n + 1}$. Now consider the limit. You get -5 as the answer.
Last edited by mr fantastic; Sep 11th 2009 at 03:45 AM. Reason: Fixed a typo.
Hi mr fantastic I think there's typo in your denominator
i think mr fantastic is right thanx guys
Originally Posted by songoku Hi mr fantastic I think there's typo in your denominator Thanks. There was. I've fixed it.
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