Show that the line containing the point (a, b) and (b, a) is perpendicular to the line y = x.

Also show that the midpoint of (a, b) and (b, a) lies on the line y = x.

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- Jan 16th 2007, 01:48 PMsymmetryLine Prove
Show that the line containing the point (a, b) and (b, a) is perpendicular to the line y = x.

Also show that the midpoint of (a, b) and (b, a) lies on the line y = x. - Jan 16th 2007, 02:02 PMSoroban
Hello, symmetry!

I must assume that you are familiar with the basic concepts needed:

. . slopes, perpendicular slopes, midpoints.

If you are not, learn or re-learn the formulas and concepts.

Quote:

Show that the line containing the points $\displaystyle (a, b)$ and $\displaystyle (b, a)$

is perpendicular to the line: $\displaystyle y = x$

The slope of the line through $\displaystyle (a,b)$ and $\displaystyle (b,a)$ is: .$\displaystyle m_1 \:=\:\frac{a-b}{b - a} \:=\:-1$

The slope of the line $\displaystyle y\:=\:x$ is: .$\displaystyle m_2 = 1$

Since $\displaystyle m_1\!\cdot\!m_2 \:=\:(-1)(1) \:=\:-1,\;\;m_1 \perp m_2$

Quote:

Show that the midpoint of $\displaystyle (a, b)$ and $\displaystyle (b, a)$ lies on the line $\displaystyle y \:= \:x$

The midpoint is: .$\displaystyle \left(\frac{a+b}{2},\,\frac{a+b}{2}\right)$

The two coordinates of the midpoint are equal.

. . Therefore, they satisfy the equation $\displaystyle y \:=\:x$

- Jan 16th 2007, 05:22 PMsymmetryok
I greatly appreciate your replies and detail explanation.