I have a review packet that will be almost exactly like a test I will have and I'm stuck on some problems and here is one that is like the rest:
If sin0= -4/7 and cos0 > 0, find sec0
I'm mostly confused because of the negative sine since obviously you can't measure a line and get negative inches.
Can someone show me how they can get the answer for this so I will be able to do similar problems to this on the test?
You know that sine, cosine and the other trig ratios all come from right triangle ratios right? Draw your x and y axes, then think about which quadrant the angle is in. Like I said because sin(x)<0, then leg parallel to the y-axis must be facing down, making it negative. Thus it has to be in the quadrant III or IV (bottom left or bottom right).
Are you with me so far?