this question assumes that you know the definition of "slope" and "y- intercept". Do you?
The slope of a straight line is where and are any two points on the line. If x= 0, then -(0+4)= 2(y- 3) so -4= 2(y-3). Dividing both sides by 2, -2= y- 3. Adding 3 to both sides, 1= y. (0, 1) is a point on the line. If x= 1, -(1+ 4)= 2(y-3) so -5= 2(y-3) and . . [tex](1, \frac{1}{2})[tex] is also a point on the line. The slope is .
The "y- intercept" is where the graph crosses ("intercepts") the y-axis which is at x= 0. Putting x= 0 into -(x+ 4)= 2(y- 3) gives -(0+ 4)= -4= 2(y- 3). Dividing both sides by 2, -2= y- 3. Adding 3 to both sides, 1= y. The "y-intercept" is either the value y= 1 or the point (0, 1) depending upon which convention your class is using.