lim (x^2 -2x -3)
x->3

lim (x-3)(x+1)
x->3

(3-3) (3+1)

because its (0) (4).. im not sure whether to times them together so its x=0 or just leave them as x=0 and x=4
thanks

2. Originally Posted by fvaras89
lim (x^2 -2x -3)
x->3

lim (x-3)(x+1)
x->3

(3-3) (3+1)

because its (0) (4).. im not sure whether to times them together so its x=0 or just leave them as x=0 and x=4
thanks
I don't see the trouble here. The value of the limit is $3^2 -2(3) - 3 = 0$. That's it. No need for factorsing etc.

3. yeah, very tempting to factor, but useless afterward because it can be evaluated directly by substitution.