1. Homework Help?

Okay, so I don't understand what I'm doing wrong, so I need some help.
lim x->3 x^2+x-6 / x^2-9
I'm supposed to find the limit, which I can't figure out

Also:
lim x->4- √x -2 / x-4
which is, again, finding the limit.

2. Originally Posted by Gengar
Okay, so I don't understand what I'm doing wrong, so I need some help.
lim x->3 x^2+x-6 / x^2-9
I'm supposed to find the limit, which I can't figure out

straight substitution of x = 3 gets you 6/0 ... what does that tell you about the limit?

Also:
lim x->4- √x -2 / x-4
which is, again, finding the limit.

hint ...

(√x -2)/(x-4) = (√x -2)/[(√x -2)(√x +2)]
...

3. Correct about the straight substitution but the thing is, the answer for that one is supposed to be 5/6 :/

4. Originally Posted by Gengar
Correct about the straight substitution but the thing is, the answer for that one is supposed to be 5/6 :/
not for the limit you posted

lim x->3 x^2+x-6 / x^2-9
... check it.

if $x \to -3$ , then the limit is $\frac{5}{6}$

5. I didn't even see the negative in front of the three in the book lol
Thank you