y = -8
can't work out x intercepts.
Can anyone help?
well i want to know how to do it , I was asked to find max , min , points of inflection etc , then to graph it. I'm not going to be able to use the internet in the middle of an exam so i am thinking it would be helpful to learn how to do it myself instead of just reading the answers of a webpage.
We haven't covered quartic equations yet so i dont even know how to do it .No wonder i can't work it out, i did'nt even know it was one.lol
understand that a sketch reflects the general shape of the graph.
I appreciate your desire to know how to solve such equations, but as stated by Mr. F, you must realize that some equations cannot be solved using elementary algebraic principles.
His original post was this, and y = -8
and this one too,
''4. Find the maxi
mum and/or minimum values and any points of inflexion of the function . Sketch the curve by using this and any other needed information.''
What is that y = -8 for? x - intercept?
i just wonder about that y = -8 THING, thanks
so then, the equation might be y = x^4 - 6x - 8?
@ x = 0, y = (0)^4 - 6(0) - 8 = -8
Now, i get it.
To get the x-intercept, set y = 0.
0 = x^4 - 6x - 8.
Solving for the roots,
x1 = -1.094;
x2 = 2.136;
x3 = -0.52 - 1.76i;
x4 = -0.52 + 1.76i
Thanks Mr Fantastic.