just 2. I got the rest down but these ones are driving me insane.

Find inverse of functions

1. h(x) = 2x/(x+10)

2. f(x) = x^2 + 6x + 11

Thanks.

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- January 14th 2007, 06:10 PMFreaky-PersonFunctions and Inverses
just 2. I got the rest down but these ones are driving me insane.

Find inverse of functions

1. h(x) = 2x/(x+10)

2. f(x) = x^2 + 6x + 11

Thanks. - January 14th 2007, 07:09 PMThePerfectHacker
- January 14th 2007, 07:49 PMFreaky-PersonQuote:

It has no inverse.

Horizontal line test, a parabola can be passes twice or more with a horizontal line.

Like the inverse of y = X^2 is y = +-sqrtX, it's still an inverse even if it's not a function.... - January 14th 2007, 07:52 PMAfterShock
- January 14th 2007, 08:04 PMAfterShock
- January 14th 2007, 08:07 PMFreaky-Person
- January 14th 2007, 08:56 PMCaptainBlack
Put:

then:

,

Now use the quadratic formula to get:

or:

.

Which is not a function when you are looking for functions from

R to R as it fails to be single valued, but it is what you are expected to

produce, and there are interpretations under which it is a function

(such as the extension of f and g to mappings from P(R) the set of

subsets of R, to itself) .

RonL - January 15th 2007, 06:21 AMThePerfectHacker
Maybe he is trying to find the inverse,

.

Meaning from the image of the function to the set of real numbers. In that case an inverse exists. - January 15th 2007, 02:55 PMFreaky-Person
Kay I got it. I'll post it up for future reference or something like that.

f(x) = x^2 + 6x + 11

y= x^2 + 6x + 11

for inverse

x = y^2 + 6y + 11

x = (y^2 + 6y + 9) + 2

x - 2 = (y + 3)^2

+-sqrt(x - 2) = y + 3

+-sqrt(x - 2) - 3 = y

BTW, anyone know any sort of tutorial for that big letter CODE writing? - January 15th 2007, 03:03 PMFreaky-Person
- January 15th 2007, 03:50 PMThePerfectHacker
I am impressed, a teenager who actually wants to learn something! I wish more of your types existed, otherwise their philosphy is simple, "If it not on the exam we do not care, we do not need it".

http://www.mathhelpforum.com/math-he...-tutorial.html