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Math Help - Help finding the removable discontinuity?

  1. #1
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    Help finding the removable discontinuity?

    It would be helpful if you could explain how you solved it also.

    For the first one, i need to know the y-intercept of this equation.

    g(x)= (x^2 + x -12) / (x-3)

    For this next one, i need to find the removable discontinuity, y-int, domain, and the function after the common factors have been eliminated.

    f(t)= (t^4 - 16) / (t^2 +4t +4)

    Thanks alot for any help.
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  2. #2
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    Quote Originally Posted by thrashattack92 View Post
    It would be helpful if you could explain how you solved it also.

    For the first one, i need to know the y-intercept of this equation.

    g(x)= (x^2 + x -12) / (x-3)

    g(0) is the y-intercept

    For this next one, i need to find the removable discontinuity, y-int, domain, and the function after the common factors have been eliminated.

    f(t)= (t^4 - 16) / (t^2 +4t +4)

    f(0) is the y-intercept

    f(t) = [(t^2+4)(t+2)(t-2)]/[(t+2)(t+2)]

    vertical asymptote at t = -2 ... so, what's the domain?

    no removable discontinuities, because one factor of (t+2) remains in the denominator.
    ...
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