# Thread: Help finding the removable discontinuity?

1. ## Help finding the removable discontinuity?

It would be helpful if you could explain how you solved it also.

For the first one, i need to know the y-intercept of this equation.

g(x)= (x^2 + x -12) / (x-3)

For this next one, i need to find the removable discontinuity, y-int, domain, and the function after the common factors have been eliminated.

f(t)= (t^4 - 16) / (t^2 +4t +4)

Thanks alot for any help.

2. Originally Posted by thrashattack92
It would be helpful if you could explain how you solved it also.

For the first one, i need to know the y-intercept of this equation.

g(x)= (x^2 + x -12) / (x-3)

g(0) is the y-intercept

For this next one, i need to find the removable discontinuity, y-int, domain, and the function after the common factors have been eliminated.

f(t)= (t^4 - 16) / (t^2 +4t +4)

f(0) is the y-intercept

f(t) = [(t^2+4)(t+2)(t-2)]/[(t+2)(t+2)]

vertical asymptote at t = -2 ... so, what's the domain?

no removable discontinuities, because one factor of (t+2) remains in the denominator.
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