If you know one of the zeroes of a polynomial, you can divide synthetically by it to reduce the polynomial one degree. So a 3rd degree becomes a 2nd degree. However, 2 is not a zero of this polynomial and neither is -2. Did you copy it wrong?
So my problem is
"Use synthetic division to show that X is a solution of the third degree polynomial equation, and use the result to factor the polynomial completely. List all the real zeros."
Polynomial Equation: Value of X = 2
I don't really understand what I'm bein asked to do..