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Thread: Simplifying Expressions with Integral Exponents

  1. September 2nd 2009, 07:15 AM #1
    JVP
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    Simplifying Expressions with Integral Exponents

    Hi, Pretty basic question. Can some look at the question I've attached and explain why when I'm simplifying

    (2a+1/b)^-2 it changes to (2ab+1/b)^-2
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  2. September 2nd 2009, 07:22 AM #2
    mathaddict
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    Quote Originally Posted by JVP View Post
    Hi, Pretty basic question. Can some look at the question I've attached and explain why when I'm simplifying

    (2a+1/b)^-2 it changes to (2ab+1/b)^-2

    (2a+\frac{1}{b})^{-2}=(\frac{2ab}{b}+\frac{1}{b})^{-2}

    When you group them into one fraction .
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  3. September 2nd 2009, 07:32 AM #3
    JVP
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    How does 2a become 2ab
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  4. September 2nd 2009, 07:38 AM #4
    mathaddict
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    Quote Originally Posted by JVP View Post
    How does 2a become 2ab

    2a+\frac{1}{b}=\frac{2a}{1}+\frac{1}{b}=\frac{2a(b )}{1(b)}+\frac{1}{b}
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