i also just figured out that the radius is 1 and the center (1,2) but what will the "4" do to the circle?
Hello! I have the following equation to graph.
4x^2+y^2+8x-y+7=0.
I know that this is a circle but I only know how to graph it when there are simply a y^2 and x^2. The other variables are confusing me..what should I do? Thank you!
i also just figured out that the radius is 1 and the center (1,2) but what will the "4" do to the circle?
No, as you were told before, it is NOT a circle, it is an "ellipse". You can write that in the "standard" form for an ellipse: ; an ellipse with center at and "semi-axes" along the x and y axes of lengths a and b. It is a circle if and only if the two "semi-axes" are the same: the radius of the circle.
The center is at (1, 2) and the semi-axes are of lengths 1/2 and 1. Draw horizontal lines (parallel to the x-axis) from (1, 2) of length 1/2 ( from (1, 2) to (1/2, 2) and (3/2, 2)) and draw vertical lines (parallel to the y-axis) from (1, 2) of length 1 (from (1, 2) to (1, 1) and (1, 3)). If you like you can draw a rectangular box with center at (1, 2) and sides y= 1, y= 3, x= 1/2, x= 3/2. The ellipse will just fit into that box.