load the attachmenthttps://www.geogebra.org/m/KrYWuNEv
see the description of the construction
slider - $ alpha $ -select the angle
slider - point P - ruler with a socket, point Q must be line n
load the attachmenthttps://www.geogebra.org/m/KrYWuNEv
see the description of the construction
slider - $ alpha $ -select the angle
slider - point P - ruler with a socket, point Q must be line n
Attachments
https://www.geogebra.org/m/HQm7WwFk
on the ruler $AB\infty{_1}\infty{_2}$ , raises divider ADC where AB + AB = AC, ruler sets the angle $\alpha$
semi-line ruler $B\infty{_1}$ sliding on point E , the point A of ruler slides semi-line l , when point C is on the line n , we get the radius of the circle , we get the angle $\beta$
we have solved the tricection of any angle
Look at the construction protocol , or find the error if there is ....
https://www.geogebra.org/m/CukhmEVy
straightedge slip on the point B - line i
divider FIG , slides on straightedge , after slipping point F straighte line BC , point G describes lokus1
section lokus1 and line k point J , when changing the angle, the point J must be manually set to the intersection
Sorry but after reviewing your posts (in this thread and others) you seem to be throwing down a gauntlet and trying to force us to find an error in your proofs with the confidence that such errors are impossible. ie. You are trying to get us to confirm your ideas instead of asking us questions. Even posting these comments in the Peer Review forum does not redeem you and repeated comments that your work is wrong doesn't seem to impress you.
Consider this fair warning. If you continue in this vein you will be banned.
Thread closed.
-Dan