Results 1 to 7 of 7

Thread: proportioned angles

  1. #1
    Junior Member
    Joined
    Jan 2012
    Posts
    68

    proportioned angles

    Required accessories - pencil, compass, unmarked straightedge


    proportioned angles-slika-1.png
    Odd proportion angles (there is a proportion of the steam angles) of the element 3 (which may be 5,7,9, ...) and the base angle  45 ^ o (which can be any angle which is obtainable by means of compass and straightedge)


    The angle CAB 45 ^ o can be obtained with a compass and unmarked ruler, he added angles (each have 45 ^ o) DAC and EAD, obtained angle EAB 135 ^ ois the starting angle


    Merge points E (D, C, B) and get a longer ED (DC, CB)


    Along the DC from the point C draw is normal that intersects the segment AB, the intersection is a point G


    Divider AG and from point G draw a circular arc to a longer EA and H get the point, and the arc GH, join the dots G and H and get along GH


    Longer GH (ED, DC, CB) are equal, the arc EB's first circular arc can be made smaller or larger with a constant radius AB, arc GH is the second circular arc can be made smaller or larger with a constant radius AG


    INCREASING THE ANGLE
    the starting angle EAB add angle FAE 15 ^ o get the angle FAB 150 ^ o - continued in the next post
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Junior Member
    Joined
    Jan 2012
    Posts
    68

    Re: proportioned angles

    - previous post was in error -

    proportioned angles-slika-1.png

    Required accessories - pencil, compass, unmarked straightedge

    basic angle - can be any angle that can be construction using compass and unmarked straightedge, angle CAB  45 ^ o

    starting angle - sum of 2, 3, 4, 5, ... basic angles , EAB  135 ^ o
    sum angles CAB  45 ^ o DAC  45 ^ o EAD  45 ^ o

    difference angle - the angle which increases or decreases the starting angle. difference starting angle and the angle of whom do not know the measure , this angle is known to see a procedure HAB  30 ^ o

    straightedge AB is divided into three parts AF , how we have a basis in the angles starting angle

    divider AF from point A the circular arc FG

    section straightedge AH the circular arc FG , point I

    straightedges FG , ED
    --------------------------------------
    will continue - if there are errors
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    Jan 2012
    Posts
    68

    Re: proportioned angles

    basic angle CAB 45^o

    starting angle EAB 135^o consists of the sum of the angles CAB 45^o DAC 45^o EAD 45^o

    DC straightedge the normal to the point D , gets the point F

    AF divider from point A, we get the point G

    divider AB from point F, divider AB from point G, we get the point H

    HG divider from point H, creates a circular arc FG

    difference angle IAB 30^o

    section IA and longer circular arc FG is a point J

    proportioned angles-slika-w.png
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor

    Joined
    Apr 2005
    Posts
    19,169
    Thanks
    2814

    Re: proportioned angles

    What was your purpose in posting this? Do you have a question? You are doing a construction but you do not say what you are trying to construct.
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Junior Member
    Joined
    Jan 2012
    Posts
    68

    Re: proportioned angles

    applies this photo
    proportioned angles-slika-3.png
    bisection angle DAC is obtained by point J
    along AJ
    GF section circular arc and along the AJ, obtained point L
    AF divider, from the point J, we get the point O
    divider AF, from point A circle c1
    divider GL, from the point J, the circuit d1, get the points P and Q
    proportioned angles-slika-3a.png
    Follow Math Help Forum on Facebook and Google+

  6. #6
    MHF Contributor

    Joined
    Apr 2005
    Posts
    19,169
    Thanks
    2814

    Re: proportioned angles

    So you are just going to keep chattering without telling us what you are talking about?
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Junior Member
    Joined
    Jan 2012
    Posts
    68

    Re: proportioned angles

    Quote Originally Posted by HallsofIvy View Post
    So you are just going to keep chattering without telling us what you are talking about?
    I found the proportion of angles to us to make sure that the process has errors
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 4
    Last Post: Jul 11th 2013, 02:25 PM
  2. principle angles and related acute angles
    Posted in the Trigonometry Forum
    Replies: 4
    Last Post: Dec 19th 2011, 06:40 AM
  3. Compound Angles or Double Angles?
    Posted in the Trigonometry Forum
    Replies: 8
    Last Post: Jul 25th 2010, 09:05 AM
  4. Help with angles?
    Posted in the Geometry Forum
    Replies: 2
    Last Post: Jun 19th 2010, 07:38 AM
  5. Replies: 1
    Last Post: Jan 7th 2009, 06:07 PM

Search Tags


/mathhelpforum @mathhelpforum