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Thread: proportioned angles

  1. #1
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    proportioned angles

    Required accessories - pencil, compass, unmarked straightedge


    proportioned angles-slika-1.png
    Odd proportion angles (there is a proportion of the steam angles) of the element 3 (which may be 5,7,9, ...) and the base angle $\displaystyle 45 ^ o$ (which can be any angle which is obtainable by means of compass and straightedge)


    The angle CAB $\displaystyle 45 ^ o$ can be obtained with a compass and unmarked ruler, he added angles (each have $\displaystyle 45 ^ o$) DAC and EAD, obtained angle EAB $\displaystyle 135 ^ o$is the starting angle


    Merge points E (D, C, B) and get a longer ED (DC, CB)


    Along the DC from the point C draw is normal that intersects the segment AB, the intersection is a point G


    Divider AG and from point G draw a circular arc to a longer EA and H get the point, and the arc GH, join the dots G and H and get along GH


    Longer GH (ED, DC, CB) are equal, the arc EB's first circular arc can be made smaller or larger with a constant radius AB, arc GH is the second circular arc can be made smaller or larger with a constant radius AG


    INCREASING THE ANGLE
    the starting angle EAB add angle FAE $\displaystyle 15 ^ o$ get the angle FAB $\displaystyle 150 ^ o$ - continued in the next post
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  2. #2
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    Re: proportioned angles

    - previous post was in error -

    proportioned angles-slika-1.png

    Required accessories - pencil, compass, unmarked straightedge

    basic angle - can be any angle that can be construction using compass and unmarked straightedge, angle CAB $\displaystyle 45 ^ o$

    starting angle - sum of 2, 3, 4, 5, ... basic angles , EAB $\displaystyle 135 ^ o$
    sum angles CAB $\displaystyle 45 ^ o$ DAC $\displaystyle 45 ^ o$ EAD $\displaystyle 45 ^ o$

    difference angle - the angle which increases or decreases the starting angle. difference starting angle and the angle of whom do not know the measure , this angle is known to see a procedure HAB $\displaystyle 30 ^ o$

    straightedge AB is divided into three parts AF , how we have a basis in the angles starting angle

    divider AF from point A the circular arc FG

    section straightedge AH the circular arc FG , point I

    straightedges FG , ED
    --------------------------------------
    will continue - if there are errors
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  3. #3
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    Re: proportioned angles

    basic angle CAB $\displaystyle 45^o$

    starting angle EAB $\displaystyle 135^o$ consists of the sum of the angles CAB $\displaystyle 45^o$ DAC $\displaystyle 45^o $EAD $\displaystyle 45^o$

    DC straightedge the normal to the point D , gets the point F

    AF divider from point A, we get the point G

    divider AB from point F, divider AB from point G, we get the point H

    HG divider from point H, creates a circular arc FG

    difference angle IAB $\displaystyle 30^o$

    section IA and longer circular arc FG is a point J

    proportioned angles-slika-w.png
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  4. #4
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    Re: proportioned angles

    What was your purpose in posting this? Do you have a question? You are doing a construction but you do not say what you are trying to construct.
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    Re: proportioned angles

    applies this photo
    proportioned angles-slika-3.png
    bisection angle DAC is obtained by point J
    along AJ
    GF section circular arc and along the AJ, obtained point L
    AF divider, from the point J, we get the point O
    divider AF, from point A circle c1
    divider GL, from the point J, the circuit d1, get the points P and Q
    proportioned angles-slika-3a.png
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  6. #6
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    Re: proportioned angles

    So you are just going to keep chattering without telling us what you are talking about?
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  7. #7
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    Re: proportioned angles

    Quote Originally Posted by HallsofIvy View Post
    So you are just going to keep chattering without telling us what you are talking about?
    I found the proportion of angles to us to make sure that the process has errors
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