Russells Paradox doesn't Exist

Russell’s Paradox: (xϵx) iff (xϵ’x)

If ϵ is different than =, xϵx is not true for any x and xϵ’x is true for all x. Therefore:

1) The left side of Russell’s Paradox does not exist, and so neither does the paradox.

2) There is no such thing as xϵx.

EDIT Think of it like Somebody's Paradox: (x<x) iff (x<'x). (x<x) doesn't exist because < is different than =.

(' means not)

Re: Russells Paradox doesn't Exist

This really belongs to the other thread on Russel's Paradox that you started.

-Dan