Russells Paradox doesn't Exist
Russell’s Paradox: (xϵx) iff (xϵ’x)
If ϵ is different than =, xϵx is not true for any x and xϵ’x is true for all x. Therefore:
1) The left side of Russell’s Paradox does not exist, and so neither does the paradox.
2) There is no such thing as xϵx.
EDIT Think of it like Somebody's Paradox: (x<x) iff (x<'x). (x<x) doesn't exist because < is different than =.
(' means not)
Re: Russells Paradox doesn't Exist
This really belongs to the other thread on Russel's Paradox that you started.