__Under Investigation__
From Points of a Transcendental Slope:

1. No more than one algebraic point exists on a line with Transcendental Slope.

To imply "y=(Pi + e) is transcendental because x=1 is algebraic" one of the following conditions must be satisfied:

- There is no algebraic point that lies on this line.
- A point on this line other than x=1, y = (Pi + e) is algebraic.

__Further Applications__
Using slope intercept form, if m = Pi, y = 0, and b=e we can solve for x:

0= (Pi/1)*x+e

x= -(e/Pi)

And thus:

The point x= -(e/Pi), y=0 also lies on a line with the transcendental slope of Pi.

Of the two points on the line with transcendental slope, coordinates x=1 and y=0 are algebraic.

From Points of a Transcendental Slope:

1. No more than one algebraic point exists on a line with Transcendental Slope.<br>

3. For all points not algebraic, if one coordinate is algebraic, the other must be transcendental.

One or both of the following coordinates:

x= -(e/Pi) or y= Pi+e

is transcendental.