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Math Help - MHFzine issue 2

  1. #1
    Grand Panjandrum
    Nov 2005

    MHFzine issue 2

    MHF-zine issue 2 is available at:

    MHFzine Issue 2 (on Google Docs)


    MHFzine Issue 2 (on a Google Groups file area)

    If you have trouble accessing the file through any of these links let me know and I will find yet another way of hosting it.

    Last edited by CaptainBlack; July 14th 2010 at 09:42 AM.
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  2. #2
    Oct 2009
    I will have to substitute for the first four problems in my second article (forthcoming in a day or two) as a mixup has occurred.

    For the last problem it should read like this:

    So he writes down:

    (2, 8, 9, 15)^3 = (3, 5, 12, 14)^3 x ? =
    (2, 8, 9, 16, 64, 72, 120, 20, 90, 150, 34, 136, 153, 255)^3 =
    (6, 10, 24, 28, 25, 60, 70, 39, 65, 156, 182, 48, 192, 224)^3 The question mark represents the multigrade you’ll need to fill in (I hope you don’t ever have this type of professor).
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  3. #3
    Oct 2009

    Thanks to Captain Black

    Captain Black has put a great deal of effort into this (second) ezine. Not only has he administered it, he also contributed some articles of his own and all this after a virus hit the website.

    It's understandable that with my second article, a few things did go wrong. LaTex is a demanding sort of program and I'm still learning its finer points (an errata will take care of the loose ends from my second article).

    To announce I've already submitted a third article for the third ezine (with a challenge). I would like to hear any comments you may have regarding my second article.

    Most of all Captain Black deserves a round of applause and welcomes further articles
    from YOU.

    Thank you for taking the time to read my article.

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  4. #4
    Oct 2009
    Article correction:

    The math professor was pleased that his class grasped the idea of multigrades so readily so he came up with four more for the class to work on. In his new challenge he wrote down the following:

    1) (5,13,18,29)^3 = (4,8,23,27)^3

    2) (5,16,19,32)^3 = (3,10,25,30)^3

    3) (1,16,19,36,54,67)^5 = (4,13,31,37,61,64)^5

    4) (1,9,13,23,35,45)^5 = (7,12,21,25,41,43)^5

    The professor said that one number needs changing in the top expression to make it a multigrade, two numbers in the second expression need changing, three numbers in the third expression need changing and four numbers in the last expression to make the fourth multigrade (the equal sign in those expressions as written is only to indicate that the expressions can be converted into multigrades).

    The professor left it as a homework assignment to convert those four expressions into multigrades within a month (for extra credit, is there more than one way of solving on each of those expressions?)

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