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Thread: Find no. of +ve intergers

  1. July 23rd 2009, 02:17 AM #1
    newtoinequality
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    Find no. of +ve intergers

    For how many positive integers n is \left(1999+ \frac{1}{2}\right)^n + \left(2000+ \frac1{2} \right)^n an integer?
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  2. July 23rd 2009, 12:03 PM #2
    TheAbstractionist
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    Hint:

    1999+\frac12\,=\,2000-\frac12
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