Help with Uspensky "sum of three squares"

I need some help with Uspensky's proof on the sum of three squares found in "Elementary Number Theory" by Uspensky and Heaslet. I have gotten to the end of the proof and do not understand a few statements found at the end. I was wondering if anyone was familiar with the proof. In it he defines $T(n)$ to be the total solutions to
$4n+1=ab+(a+b-2)c$
$4n+1=ab+(a+b+2)c$
With $a+b \equiv 0 \pmod 4$ and $a,b,c$ all odd.
Let $N_3(n)$ be the number of representations of $n$ as the sum of three squares.
He shows $2[T(4d-1^2)+T(4d-3^2)+T(4d-5^2)+\ldots ]=N_3(4d-1^2)+N_3(4d-3^2)+N_3(4d-5^2)+\ldots$
Which I understand where that comes from. What I am confused on, is he claims that since this identity is true for all odd values of $m$ that we must have
$2T(4d-1^2)=N_3(4d-1^2)$
Why must we have that? Any help would be greatly appreciated.