1. ## Proof Help

How do you prove the attached question please?

I've got nowhere with it for days!

2. This problem has been partially 'attacked' here...

http://www.mathhelpforum.com/math-he...e-numbers.html

Kind regards

$\displaystyle \chi$ $\displaystyle \sigma$

3. ## Still stuck

I'm not quite sure how this partial solutions relates to my question. Sorry for being dumb!

I've been reading Apostol's Analytic Number Theory and wondered if the proof of Thm 4.12 could be adapted to prove the result. Is that possible?

4. Sorry ... i did'nt read carrefully your pdf file and intended the expression...

$\displaystyle \sum_{p\le x} \frac{1}{p}$

... as the sum of reciprocal of prime numbers less or equal to $\displaystyle x$ , whereas it is clearly reported that $\displaystyle p$ are the numbers less or equal to $\displaystyle x$ that satisfy the equation...

$\displaystyle p= 3 \mod{10}$

How silly of me! ... The solution requires little more time...

Kind regards

$\displaystyle \chi$ $\displaystyle \sigma$

5. is anyone able to help with this problem?