How do you prove the attached question please?
I've got nowhere with it for days!
This problem has been partially 'attacked' here...
http://www.mathhelpforum.com/math-he...e-numbers.html
Kind regards
$\displaystyle \chi$ $\displaystyle \sigma$
Sorry ... i did'nt read carrefully your pdf file and intended the expression...
$\displaystyle \sum_{p\le x} \frac{1}{p}$
... as the sum of reciprocal of prime numbers less or equal to $\displaystyle x$ , whereas it is clearly reported that $\displaystyle p$ are the numbers less or equal to $\displaystyle x$ that satisfy the equation...
$\displaystyle p= 3 \mod{10}$
How silly of me! ... The solution requires little more time...
Kind regards
$\displaystyle \chi$ $\displaystyle \sigma$