Question

If x^3+y^3=z^3 has a solution in integers x, y, z, show that one of the three must be a multiple of 7.

How should I solve this question?

Thank you very much.

Results 1 to 2 of 2

- Jan 3rd 2007, 12:14 PM #1

- Joined
- Nov 2006
- Posts
- 123

- Jan 3rd 2007, 12:22 PM #2

- Joined
- Nov 2005
- From
- New York City
- Posts
- 10,616
- Thanks
- 10