1. ## a difficult problem

A number has 24 factors.The multiplication of its prime factors is 30(taking 1 at a time).What is the ratio of the square roots of the highest and the smallest such number possible?

2. Originally Posted by jashansinghal
A number has 24 factors.The multiplication of its prime factors is 30(taking 1 at a time).What is the ratio of the square roots of the highest and the smallest such number possible?

The hard part is the first sentence. You know the primes that divide such a number (as these are the primes that multiply to get 30), and the powers of the primes sum to 24 and are all non-zero (as otherwise the product would not be 24). So, what is the largest number possible? What is the smallest?

Big hint: let $x=p_1^{a_1}p_2^{a_2} \ldots p_n^{a_n}$ be such a number, with $p_1. Then the largest is the one with $a_1=a_2= \ldots = a_{n-1} = 1$ and $a_n = 24-(n-1)$.

(Unless I'm missing something here?)

3. I took jashansinghal’s first line to mean 24 factors, not 24 prime factors. But then I’m unable to find any integer with exactly 24 factors. Maybe I’m missing something as well.

4. Originally Posted by TheAbstractionist
I took jashansinghal’s first line to mean 24 factors, not 24 prime factors. But then I’m unable to find any integer with exactly 24 factors. Maybe I’m missing something as well.
Well, I wasn't sure what "24 factors" meant otherwise. 24 ways of factorising it, perhaps? 5 has one way, 6 has two ways (6 and 2.3) etc, but I thought that a bit far fetched...

5. Hello,

For example, 6 has 4 factors : 1,2,3,6

If I'm not mistaking (hasn't seen this for a while) : the number of factors of a number $n=p_1^{\alpha_1}\cdot p_2^{\alpha_2} \cdots p_m^{\alpha_m}$ is $\prod_{k=1}^m \{\alpha_k+1\}$

So here, we have $\prod_{k=1}^m \{\alpha_k+1\}=24$

And the product of its prime factors is 30 : $\prod_{k=1}^m p_k=30$

Then, we have to be able to find the smallest and greatest possible numbers responding to these conditions... So I'm pretty sure we have to study the prime decomposition of 30
But now... I have to take a shower

6. Each of these has 24 factors: $2^3\cdot 3^2\cdot 5=360~\&~2\cdot 3^2\cdot 5^3=2250$.
If I understand the bit about the product being 30 then they are smallest and largest.

7. Originally Posted by Plato
Each of these has 24 factors: $2^3\cdot 3^2\cdot 5=360~\&~2\cdot 3^2\cdot 5^3=2250$.
So they do! Now how in the world did I miss those?

8. $2\cdot 3\cdot 5^5>2\cdot 3^2 \cdot 5^3$ and satisfies all the conditions...

9. Originally Posted by Moo
$2\cdot 3\cdot 5^5>2\cdot 3^2 \cdot 5^3$ and satisfies all the conditions...
I am willing to bet that who ever wrote that question also missed that solution.
Because it almost makes this question pointless: “What is the ratio of the square roots of the highest and the smallest such number possible?”

10. Originally Posted by Plato
I am willing to bet that who ever wrote that question also missed that solution.
Because it almost makes this question pointless: “What is the ratio of the square roots of the highest and the smallest such number possible?”
Completely agree.
Yours is aesthetically more beautiful lol

11. Originally Posted by Plato
Each of these has 24 factors: $2^3\cdot 3^2\cdot 5=360~\&~2\cdot 3^2\cdot 5^3=2250$.
If I understand the bit about the product being 30 then they are smallest and largest.
how can you get the solution without doing hit and trial method

12. All right guys, I just remembered this: the tau function $\tau(n)$ which gives the number of factors of each integer $n > 1.$ $\tau$ has the following property: if $n=p_1^{k_1}\cdots p_r^{k_r}$ where the $p_i$ are distinct primes, then

$\tau(n)\ =\ \prod_{i\,=\,1}^r(1+k_i)$

So for this particular problem, the distinct primes are 2, 3, and 5 and the number is of the form $2^a3^b5^c$ where $(1+a)(1+b)(1+c)=24.$ The possibilities are thus

(i) $a=1,\,b=1,\,c=5$
(ii) $a=1,\,b=5,\,c=1$
(iii) $a=5,\,b=1,\,c=1$
(iv) $a=1,\,b=2,\,c=3$
(v) $a=1,\,b=3,\,c=2$
(vi) $a=2,\,b=1,\,c=3$
(vii) $a=2,\,b=3,\,c=1$
(viii) $a=3,\,b=1,\,c=2$
(ix) $a=3,\,b=2,\,c=1$

The largest number is therefore $2^13^15^5$ and the smallest is $2^33^25^1.$ Hence the answer to the question is $\sqrt{\frac{2^13^15^5}{2^33^25^1}}\,=\,\frac{25}{2 \sqrt3}.$

13. Originally Posted by TheAbstractionist
All right guys, I just remembered this: the tau function $\tau(n)$ which gives the number of factors of each integer $n > 1.$ $\tau$ has the following property: if $n=p_1^{k_1}\cdots p_r^{k_r}$ where the $p_i$ are distinct primes, then

$\tau(n)\ =\ \prod_{i\,=\,1}^r(1+k_i)$

So for this particular problem, the distinct primes are 2, 3, and 5 and the number is of the form $2^a3^b5^c$ where $(1+a)(1+b)(1+c)=24.$ The possibilities are thus

(i) $a=1,\,b=1,\,c=5$
(ii) $a=1,\,b=5,\,c=1$
(iii) $a=5,\,b=1,\,c=1$
(iv) $a=1,\,b=2,\,c=3$
(v) $a=1,\,b=3,\,c=2$
(vi) $a=2,\,b=1,\,c=3$
(vii) $a=2,\,b=3,\,c=1$
(viii) $a=3,\,b=1,\,c=2$
(ix) $a=3,\,b=2,\,c=1$

The largest number is therefore $2^13^15^5$ and the smallest is $2^33^25^1.$ Hence the answer to the question is $\sqrt{\frac{2^13^15^5}{2^33^25^1}}\,=\,\frac{25}{2 \sqrt3}.$
Well, basically, you're just rewording and explaining the steps of what has been said above

14. Originally Posted by Moo
Well, basically, you're just rewording and explaining the steps of what has been said above
Yes, and I should have done it much sooner.