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Math Help - another question

  1. #1
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    another question

    show that [a1,a2,...,an-1,an] = [[a1,a2,...,an-1],an]
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  2. #2
    MHF Contributor Bruno J.'s Avatar
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    What is that? Least common multiple?
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  3. #3
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    Quote Originally Posted by Bruno J. View Post
    What is that? Least common multiple?

    yes, least common multiple.
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  4. #4
    MHF Contributor Bruno J.'s Avatar
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    Try using the fact that if a=p^\alpha m, b=p^\beta n with p \nmid mn, then the largest power of p which divides [a,b] is p^{\mbox{ max}(a,b)}.
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