# Math Help - another question

1. ## another question

show that [a1,a2,...,an-1,an] = [[a1,a2,...,an-1],an]

2. What is that? Least common multiple?

3. Originally Posted by Bruno J.
What is that? Least common multiple?

yes, least common multiple.

4. Try using the fact that if $a=p^\alpha m, b=p^\beta n$ with $p \nmid mn$, then the largest power of p which divides $[a,b]$ is $p^{\mbox{ max}(a,b)}$.