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**Keep** The questions:

1) There are 8 free rooms in a hostel. How many ways can 4 students be divided into these rooms?

2) A student must choose 5 question from a 12 question exam paper. If he chooses at least 3 from the first 6, calculate the number of ways he can choose.

My answers:

1) Since order does not matter, we calculate as such: $\displaystyle \left(^{8}\mathcal{P}_5\right)$ which will give us 5040. Is this right or am I doing something wrong?

2)Choosing at least 3 from the first 6 it will give 12X11X10 = 1320. From here, I am stuck assuming I was right upto here in the first place.