For n=1, .
Now Assume for some k>1
then by the induction step
and which is what we wanted to show
i think this one is pretty easy but i'm not that great with induction. any help?
Show that for any integer n that is an element of
my attempt:
base case - let n=1
2^1=2 > 1 -> base case is true
2^(n+1) > n+1
2^n + 2 > n+1
2^n > n-1
statement holds true by the base case 2^1 > 1-1