i think this one is pretty easy but i'm not that great with induction. any help?

Show that for any integer n that is an element of

my attempt:

base case - let n=1

2^1=2 > 1 -> base case is true

2^(n+1) > n+1

2^n + 2 > n+1

2^n > n-1

statement holds true by the base case 2^1 > 1-1