gcd(840,354)=6
thus 6=a(840)+b(354) for some a,b both integers
this solves to a=-8 and b=19
therefore if you have 6n=840x+354y then i suppose x=-8n and y=19n
"Express all integer solutions in terms of n to the equation 840x+354y=6n, where n is natural." please
First I used the highest common factor method to find solutions for 840x+354y=6
solutions are
x=354m-8
y=19-840m
not sure what to do about 6n.
I really need an answer for this one please, anything you have that might help would be greatly appreciated.