Prove that if u < v and x < y, then u+x < v+y. Also if x < y and z < 0, then y*z < x*z.
Follow Math Help Forum on Facebook and Google+
Originally Posted by noles2188 Prove that if u < v and x < y, then u+x < v+y. Also if x < y and z < 0, then y*z < x*z. I dunno what axioms you can use.
Last edited by Gamma; April 28th 2009 at 08:37 PM. Reason: Quote
View Tag Cloud