Prove that if u < v and x < y, then u+x < v+y.

Also if x < y and z < 0, then y*z < x*z.

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- April 28th 2009, 09:29 PMnoles2188Order of Numbers Proofs
Prove that if u < v and x < y, then u+x < v+y.

Also if x < y and z < 0, then y*z < x*z. - April 28th 2009, 09:36 PMGamma