Prove that if u < v and x < y, then u+x < v+y.

Also if x < y and z < 0, then y*z < x*z.

Printable View

- Apr 28th 2009, 08:29 PMnoles2188Order of Numbers Proofs
Prove that if u < v and x < y, then u+x < v+y.

Also if x < y and z < 0, then y*z < x*z. - Apr 28th 2009, 08:36 PMGamma