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Math Help - Perfect powers of a particular form

  1. #16
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    factoring 5 would affect c wouldnt it, because its 5^c...

    also, so can u assume that if 2,3 and 5 are taken as factors, then the powers are also divisible by 2, 3 and 5?
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  2. #17
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    Sorry, just fixed a typo in my last post.
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  3. #18
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    Hi, i got to the number being m=2^a * 3^b * 5^c

    but how do yout hypthesise these situations:
    where (1) b and c are even but a is odd, (2) a and c are divisible by 3 but b leaves a remainder of 1, and (3) a and b are divisible by 5, but c leaves a remainder of 1.

    without having worked out the solution being m=30233088000000 yet
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  4. #19
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    oops supid question, i just saw u replied to that nvm!

    thanks a lot! this was really helpful!
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