factoring 5 would affect c wouldnt it, because its 5^c...

also, so can u assume that if 2,3 and 5 are taken as factors, then the powers are also divisible by 2, 3 and 5?

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- May 3rd 2009, 10:40 AMAquafina
factoring 5 would affect c wouldnt it, because its 5^c...

also, so can u assume that if 2,3 and 5 are taken as factors, then the powers are also divisible by 2, 3 and 5? - May 3rd 2009, 10:59 AMMedia_Man
Sorry, just fixed a typo in my last post.

- May 3rd 2009, 09:55 PMAquafina
Hi, i got to the number being m=2^a * 3^b * 5^c

but how do yout hypthesise these situations:

where (1) b and c are even but a is odd, (2) a and c are divisible by 3 but b leaves a remainder of 1, and (3) a and b are divisible by 5, but c leaves a remainder of 1.

without having worked out the solution being m=30233088000000 yet - May 3rd 2009, 10:22 PMAquafina
oops supid question, i just saw u replied to that nvm!

thanks a lot! this was really helpful!