assumptions: p is a prime number.
1<= a <= (p-1)
the order of a modulo p is d
describe the solutions of the congruence x^d congr. 1 (mod p) in terms of a. Does this give all the solutions of x^d congr. 1 (mod p) ?
I'm really blanking for some reason... obviously any power of a works but...where to go from there?