prove that any number that is a square must have one of the following for its units digit: 0,1,4,5,6,9.

Results 1 to 3 of 3

- February 26th 2009, 02:18 PM #1

- Joined
- Feb 2009
- Posts
- 40

- February 26th 2009, 03:34 PM #2

- Joined
- Nov 2005
- From
- New York City
- Posts
- 10,616
- Thanks
- 9

- February 26th 2009, 04:04 PM #3
Consider a two digit number with unit digit as a and tens digit as b

So a and b both are positive interger less than 10

So number can be written as 10b + a

Now

Now and both have 0 at unit place. So unit digit of will be decided by

And for a being single digit integer, you only get 0,1,4,5,6,9.at units place of

You can extend this proof for three digit number 100c + 10b + a.

Same logic will be applied in this case