Prove that the highest common factor of

and = 1, where for some prime p and natural number m.

Printable View

- February 23rd 2009, 04:12 PMAmanda1990Prove hcf(a,b) =1 where a,b are as follows...
Prove that the highest common factor of

and = 1, where for some prime p and natural number m. - February 25th 2009, 11:30 PMtah
If the hcf you mentioned is the same as greatest common divisor (I don't what's the difference between them, if there is!!) then you can notice that any factor of q is power of p then p divide the hcf if it isn't equal to 1. Therefore

which implies, for some (property of prime elements) which is impossible. So the hcf is 1.