Prove that the longer leg of a Pythagorean triple can never be twice the shorter leg.
I know that I need to prove this indirectly. I am just having trouble coming to a contradiction.
Prove that the longer leg of a Pythagorean triple can never be twice the shorter leg.
I know that I need to prove this indirectly. I am just having trouble coming to a contradiction.
If $\displaystyle x^2+y^2 = (2x)^2 \implies y^2 = 3x^2$ and this is the contradition because that equation is impossible for positive integers.