3x^5=1 (mod 29)
3^x=2 (mod 29)
find all solutions for both congruences.
Follow Math Help Forum on Facebook and Google+
Originally Posted by mathisthebestpuzzle 3x^5=1 (mod 29) Write, (since is an inverse of mod ).
Now find the index of for a given primitive root of .
Can you finish up the problem?
hacker i thank you so much, but i had already solved that one since i posted it.
i am stuck on the second one though...any help would be wonderful!
View Tag Cloud