x=2 (mod 5), 2x=3 (mod 7), 3x=4 (mod 11)

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- February 17th 2009, 03:25 AMSally_Mathsolve the system
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__=__2 (mod 5), 2x__=__3 (mod 7), 3x__=__4 (mod 11) - February 17th 2009, 03:27 AMMoo
- February 17th 2009, 03:44 AMSally_Math
- February 17th 2009, 09:30 PMThePerfectHacker