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Math Help - Please Help

  1. #1
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    Please Help

    d(360) = 24 because 360 = (2^3)+(3^2)+(5^1)
    (3+1)(2+1)(1+1)=24

    Prove d(n) is odd if n is a perfect square.
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  2. #2
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    Let n=a^2=(p_{1}^{k_{1}}p_{2}^{k_{2}}\dots p_{r}^{k_{r}})^2 =(p_{1}^{2k_{1}}p_{2}^{2k_{2}}\dots p_{r}^{2k_{r}}) where all the p's are distinct primes.

    Now show d(n) is a product of odd numbers and hence d(n) is odd.
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  3. #3
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    thank you
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