Thread: Persistent squares

The following number is a persistent square:

82^2 = 7396==>73+96 = 169 = 13^2 1=6=9 = 4^2

Find 5 more persistent squares.

What is a good way of showing and explaining this?

Hello, t-lee!

Could you re-state the problem ?
I can't follow the procedure . . .

The following number is a persistent square:
. . 82² = 7396 . . . but this is not true!

Then: .73 + 96 .= .169 . . . we "split" the number and add?

And: .169 .= .13^2 . . . and the sum is a square?

Then: .1 = 6 = 9 = 4² . . . What happened here?

Find 5 more persistent squares.

I'd love to . . . but what exactly is a "persistent square"?

Originally Posted by t-lee

The following number is a persistent square:

82^2 = 7396==>73+96 = 169 = 13^2 1=6=9 = 4^2

Find 5 more persistent squares.

What is a good way of showing and explaining this?

I must say, I've never seen anything like this before...

I'm going ot define a persistant square as:

Originally Posted by Quicktionary "Persistant Square"

a perfect square that when the left half of it's digits are added to the right have of it's digits form a number "n" which is a perfect square. The digits of "n" added together also equal a perfect square.

I will help you as soon as Latex is back online (because this could get confusing without it)