Hello, t-lee!

Could you re-state the problem ?

I can't follow the procedure . . .

The following number is a persistent square:

. . 82² = 7396 . . . but this is not true!

Then: .73 + 96 .= .169 . . . we "split" the number and add?

And: .169 .= .13^2 . . . and the sum is a square?

Then: .1 = 6 = 9 = 4² . . . What happened here?

Find 5 more persistent squares.

I'd love to . . . but what exactly is a "persistent square"?