The following number is a persistent square:
82^2 = 7396==>73+96 = 169 = 13^2 1=6=9 = 4^2
Find 5 more persistent squares.
What is a good way of showing and explaining this?
Hello, t-lee!
Could you re-state the problem ?
I can't follow the procedure . . .
The following number is a persistent square:
. . 82² = 7396 . . . but this is not true!
Then: .73 + 96 .= .169 . . . we "split" the number and add?
And: .169 .= .13^2 . . . and the sum is a square?
Then: .1 = 6 = 9 = 4² . . . What happened here?
Find 5 more persistent squares.
I'd love to . . . but what exactly is a "persistent square"?