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Math Help - Persistent squares

  1. #1
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    Persistent squares

    The following number is a persistent square:

    82^2 = 7396==>73+96 = 169 = 13^2 1=6=9 = 4^2

    Find 5 more persistent squares.

    What is a good way of showing and explaining this?
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  2. #2
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    Hello, t-lee!

    Could you re-state the problem ?
    I can't follow the procedure . . .


    The following number is a persistent square:
    . . 82 = 7396 . . . but this is not true!

    Then: .73 + 96 .= .169 . . . we "split" the number and add?

    And: .169 .= .13^2 . . . and the sum is a square?

    Then: .1 = 6 = 9 = 4 . . . What happened here?

    Find 5 more persistent squares.

    I'd love to . . . but what exactly is a "persistent square"?

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  3. #3
    MHF Contributor Quick's Avatar
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    Quote Originally Posted by t-lee View Post
    The following number is a persistent square:

    82^2 = 7396==>73+96 = 169 = 13^2 1=6=9 = 4^2

    Find 5 more persistent squares.

    What is a good way of showing and explaining this?
    I must say, I've never seen anything like this before...

    I'm going ot define a persistant square as:

    Quote Originally Posted by Quicktionary "Persistant Square"
    a perfect square that when the left half of it's digits are added to the right have of it's digits form a number "n" which is a perfect square. The digits of "n" added together also equal a perfect square.
    I will help you as soon as Latex is back online (because this could get confusing without it)
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