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Math Help - Srinivasa Ramanujan proved that 1+2+3+... = -1/12???

  1. #1
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    Srinivasa Ramanujan proved that 1+2+3+... = -1/12???

    Went to see dissapearing number last night at the Barbican. Apparently,

    Srinivasa Ramanujan proved that 1+2+3+... = -1/12, I believe using the zet function?

    Can anyone explain how this can be. I am high sch maths teacher, but would like to see how this is proved.
    If you can help, I would really appreciate it.

    Thanks

    Mrt1
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by mrt1 View Post
    Went to see dissapearing number last night at the Barbican. Apparently,

    Srinivasa Ramanujan proved that 1+2+3+... = -1/12, I believe using the zet function?

    Can anyone explain how this can be. I am high sch maths teacher, but would like to see how this is proved.
    If you can help, I would really appreciate it.

    Thanks

    Mrt1
    Google for "Ramanujan summation"

    CB
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  3. #3
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    sr ramanujan's summation to equal -1/12

    I need some help with this. Every wb page I look at is either full of maths, I've not seen for years, or these is a proof in a physics forum that

    Ramanujan Summation and Divergent series in relation to the Riemann Zeta function. I'm not sure is concrete.

    What is the R next to the -1/12?

    Mark
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  4. #4
    Grand Panjandrum
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    Quote Originally Posted by mrt1 View Post
    I need some help with this. Every wb page I look at is either full of maths, I've not seen for years, or these is a proof in a physics forum that

    Ramanujan Summation and Divergent series in relation to the Riemann Zeta function. I'm not sure is concrete.

    What is the R next to the -1/12?

    Mark
    It denote that the summation in question is not a normal summation (which is just as well since the series are in any conventional sense are divergent), but is a Ramanujan sum, which is a rather different beast.

    CB
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