See attachment. Thanks
Last edited by bigb; Oct 18th 2008 at 02:02 PM.
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1) $\displaystyle \sigma (p^k) = \frac{p^{k+1} - 1}{p-1}$ where $\displaystyle p$ is prime. 2) $\displaystyle \sigma (nm) = \sigma( n ) \sigma (m)$ for relatively prime positive integers. With that you can solve the problem.
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