Suppose g is a primitive root modulo p (a prime) and suppose m|p-1 (1<m<p-1). How many solutions are there to the congruence:
(mod p)
My attempt:
(mod )
(mod )
(mod )
(mod p)
Hence g=1 which is a contradiction so there are no solutions.
I don't believe my own answer! I have not used the statement that
m|p-1 which tells me that g.c.d(m, = m