I believe you are trying to use Permutations and Combinations!!

Let me help you a bit.

Say you have 4 distinct wine bottles(A,B,C and D) and you want to select 3

AAA isnt an option since there are only 4 bottles

However ABC is the same as BAC,CBA .......

So from 4 bottles number of ways of selecting 3 is given by 4C3 and solved as

(4x3x2)/(1x2x3) which is basically 4 ways.

There's a whole lot more!!