I believe you are trying to use Permutations and Combinations!!
Let me help you a bit.
Say you have 4 distinct wine bottles(A,B,C and D) and you want to select 3
AAA isnt an option since there are only 4 bottles
However ABC is the same as BAC,CBA .......
So from 4 bottles number of ways of selecting 3 is given by 4C3 and solved as
(4x3x2)/(1x2x3) which is basically 4 ways.
There's a whole lot more!!