using a table of indices mod 37 find the solutions.....

7x^20==34(mod37)

I(7x^20) == I(34) (mod 36)

I(7) + I(x^20) == I(34)

I(7) + 20 (I(x)) == I (34)

subtract I(7) from both sides

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20(I(x)) ==I(34) - I(7)

20x = 34-7

20x = 27 (mod 36)

From this point I'm lost....I know that the gcd (20, 36) = 4 therefore there are 4 solutions, but I can't seem to move past this point...