1. Originally Posted by ThePerfectHacker
I believe it is
Kings 1:22:7

And he made a molten sea, ten cubits from the one brim to the other; it was round all about, and its height was five cubits; a line of thirty cubits did compass it around

It is possible that we disagree perhaps, you follow the King James Version, I was following the original Bible Text.
Shouldn't it be 1 Kings 22:7?
The original Bilble Text is Hebrew, can you read it?

Which makes it interesing cuz, if you divide the verse by the chapter you get, 22/7.
It's proof of the Bible Code
(even though I believe in the Bible, I think this Bible code stuff is nonsense)

Going back on topic....

Does anyone know pi in decimal form to the fourteenth decimal? I would like to compare my approximation of 3.14159265358979 to the actual number.

2. Originally Posted by Quick
Shouldn't it be 1 Kings 22:7?
The original Bilble Text is Hebrew, can you read it?
Yes.

Originally Posted by Quick
Does anyone know pi in decimal form to the fourteenth decimal? I would like to compare my approximation of 3.14159265358979 to the actual number.
Code:
3.14159 26535 89793 23846 26433  83279 50288 41971 69399 37510
58209 74944 59230 78164 06286  20899 86280 34825 34211 70679
82148 08651 32823 06647 09384  46095 50582 23172 53594 08128
48111 74502 84102 70193 85211  05559 64462 29489 54930 38196
44288 10975 66593 34461 28475  64823 37867 83165 27120 19091

45648 56692 34603 48610 45432  66482 13393 60726 02491 41273
72458 70066 06315 58817 48815  20920 96282 92540 91715 36436
78925 90360 01133 05305 48820  46652 13841 46951 94151 16094
33057 27036 57595 91953 09218  61173 81932 61179 31051 18548
07446 23799 62749 56735 18857  52724 89122 79381 83011 94912

3. ## That turned out to not be such a quick question.

Thanx

4. Originally Posted by Jameson
Aren't the last two kind of repetitive PH?

$\displaystyle \Gamma(z)=2\int_{0}^{\infty}e^{-t^2}t^{2z-1}dz$
After some manipulation, slightly.

5. Originally Posted by Soroban

$\displaystyle \frac{22}{7}$ . . . . upper bound found by Archimedes, 3rd century B.C.

Archimedes is rather modern in that he does not give a single estimate
but an interval estimate of $\displaystyle \pi$. As I said before his method
is to trap the area of a circle between a sequence of circumscribed and
inscribed regular polygons, which produces upper and lower limits for
the value of $\displaystyle \pi$.

Archimedes uses polygons of 96 sides and finds:

$\displaystyle 223/71<\pi<22/7$.

RonL

6. Hacker, you agree $\displaystyle \sqrt{-25}=5i$

but you say you cannot solve for negative square roots. How would you solve? (preferably showing all the work)

7. Originally Posted by Quick
Hacker, you agree $\displaystyle \sqrt{-25}=5i$

but you say you cannot solve for negative square roots. How would you solve? (preferably showing all the work)
I think this post looks lost, should it not be in a different thread?

RonL

8. ## oops

Originally Posted by CaptainBlack
I think this post looks lost, should it not be in a different thread?

RonL
It's funny, I blanked out and thought this was my "imaginary numbers " thread
just one of those moments...

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