Prove that:

(1) $\displaystyle \sum_{d|n}\tau^3(d) = \left(\sum_{d|n}\tau(d)\right)^2$

(2)$\displaystyle \prod_{d|n}d = n^{\frac{\tau(n)}{2}}$

These come from my Arithmetic functions section in my book. $\displaystyle \tau$ is a divisor function and is multiplicative.

Thanks for any help!