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Math Help - Modules

  1. #1
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    Modules

    Anyone know anything about modules?

    I have this sample problem but i dont understand the transition from step 3 to 4

    1. 11x +8 =16 (mod 26)
    2. 11x=8
    3. (11^-1)*11x=(11^-1)*8
    4. x=19*8=152=100=48=22

    thanks
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  2. #2
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    Quote Originally Posted by laucoyne View Post
    Anyone know anything about modules?

    I have this sample problem but i dont understand the transition from step 3 to 4

    1. 11x +8 =16 (mod 26)
    2. 11x=8
    3. (11^-1)*11x=(11^-1)*8
    4. x=19*8=152=100=48=22

    thanks
    The multiplicative inverse of 11 in mod 26 is 19. That is to say
    19 \cdot 11 \equiv 1~\text{(mod 26)}

    -Dan
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