Anyone know anything about modules? I have this sample problem but i dont understand the transition from step 3 to 4 1. 11x +8 =16 (mod 26) 2. 11x=8 3. (11^-1)*11x=(11^-1)*8 4. x=19*8=152=100=48=22 thanks
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Originally Posted by laucoyne Anyone know anything about modules? I have this sample problem but i dont understand the transition from step 3 to 4 1. 11x +8 =16 (mod 26) 2. 11x=8 3. (11^-1)*11x=(11^-1)*8 4. x=19*8=152=100=48=22 thanks The multiplicative inverse of 11 in mod 26 is 19. That is to say $\displaystyle 19 \cdot 11 \equiv 1~\text{(mod 26)}$ -Dan
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