How can I prove that 153 is the only number for which "number = 17 * sum of the number's digits" (153 = 17*(1+5+3)) is true?
Thanks
First off, x must evidently be divisible by 17, x = 17n.Originally Posted by Alex F.
Also, x cannot have more than three digits, x = abc, because otherwise n = x/17 would be larger than 1000/17 > 58. Then there would have to be at least seven digits (because each digit contributes at most 9 to this sum), so x/17 would have to be larger than 10,000,000/17 > 580000. Therefore there would have to be at least 70,000 digits, and so on, a contradiction.
Suppose now x has the digits abc, that is x = c+10b+100a.
Then you want also x = 17*(a+b+c), and a, ..., g must be integers from the list {0,1,2,...,9}. Work with this to prove that a=1, b=5, c=3.