How can I prove that 153 is the only number for which "number = 17 * sum of the number's digits" (153 = 17*(1+5+3)) is true?

Thanks :)

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- May 30th 2005, 04:18 AMAlex F.proof
How can I prove that 153 is the only number for which "number = 17 * sum of the number's digits" (153 = 17*(1+5+3)) is true?

Thanks :) - Jun 5th 2005, 10:33 PMbeepnoodle
Suppose that there is another solution, call it x. Show that x must be equal to 153. This shows that your solution is unique.

- Jun 6th 2005, 04:32 AMhpeQuote:

Originally Posted by**Alex F.**

Also, x cannot have more than three digits, x = abc, because otherwise n = x/17 would be larger than 1000/17 > 58. Then there would have to be at least seven digits (because each digit contributes at most 9 to this sum), so x/17 would have to be larger than 10,000,000/17 > 580000. Therefore there would have to be at least 70,000 digits, and so on, a contradiction.

Suppose now x has the digits abc, that is x = c+10b+100a.

Then you want also x = 17*(a+b+c),**and**a, ..., g must be integers from the list {0,1,2,...,9}. Work with this to prove that a=1, b=5, c=3.