Prove that there is no rational root whose square is 12?
I use the proof based on Euclid's Method.Originally Posted by Nichelle14
Do you know that one? It is completely analogous answering your question "Can it do it like sqrt of 2?".
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Look here
I can show you how to use this theorem to prove that it irrational.
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Susie38 and Nichelle14 Related?
Are you the same user?
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Note, what I prove in that thread in the end is this. "That a square root of an integral number is either integral or irrational"
Note that there is no integer such as, $\displaystyle x^2=12$ why? Very simple, note the first few values,
$\displaystyle 1^2=1,2^2=4,3^2,=9,4^2=16$ it never gives 12, since anything thing greater then 4, will for certainly give a value greater than 12 because this sequence of square are increasing they are simply to big to be equal to 12, thus there is no such $\displaystyle x$. Thus, by the theorem its root must be irrational.
yes. the same. I forgot my password, but figured it out. Does it matter? Should i only use one? Also it depends on what computer i log in at home. I don't always pay attention to what my user name is at the time. My computer automatically remembers the user name and password.