Prove that there is no rational root whose square is 12?

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- Jun 11th 2006, 04:46 PMNichelle14Can I do it like the proof for sqrt of 2
Prove that there is no rational root whose square is 12?

- Jun 11th 2006, 05:13 PMThePerfectHackerQuote:

Originally Posted by**Nichelle14**

Do you know that one? It is completely analogous answering your question "Can it do it like sqrt of 2?".

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Look here

I can show you how to use this theorem to prove that it irrational. - Jun 11th 2006, 05:36 PMSusie38
no I do not know.

- Jun 11th 2006, 06:02 PMThePerfectHacker
How are

Susie38 and Nichelle14 Related?

Are you the same user?

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Note, what I prove in that thread in the end is this. "That a square root of an integral number is either integral or irrational"

Note that there is no integer such as, $\displaystyle x^2=12$ why? Very simple, note the first few values,

$\displaystyle 1^2=1,2^2=4,3^2,=9,4^2=16$ it never gives 12, since anything thing greater then 4, will for certainly give a value greater than 12 because this sequence of square are increasing they are simply to big to be equal to 12, thus there is no such $\displaystyle x$. Thus, by the theorem its root must be irrational. - Jun 11th 2006, 07:51 PMSusie38
yes. the same. I forgot my password, but figured it out. Does it matter? Should i only use one? Also it depends on what computer i log in at home. I don't always pay attention to what my user name is at the time. My computer automatically remembers the user name and password.

- Jun 12th 2006, 10:23 AMThePerfectHackerQuote:

Originally Posted by**Susie38**

You can ask the administrator to reset your password, if that is necessary. Also, you can sent yourself an e-mail with the password.